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GUJCET · Physics · Moving Charges and Magnetism
Circular loop having radius \(r\), carrying current I , produces magnetic field at the centre of loop is \(B\), What will be the magnetic dipole moment of this loop?
- A \(\frac{2 \pi Br^3}{\mu_0}\)
- B \(\frac{\pi B r^3}{\mu_0}\)
- C \(\frac{4 \pi Br { }^3}{\mu_0}\)
- D \(\frac{\pi B r^3}{4 \mu_0}\)
Answer & Solution
Correct Answer
(A) \(\frac{2 \pi Br^3}{\mu_0}\)
Step-by-step Solution
Detailed explanation
Magnetic moment \(=i A\) \(\quad \quad \ldots \ldots(1)\)
Magnetic field of circular loop
\(\begin{array}{l} B =\frac{\mu_0}{2} \frac{i}{r} \\ i=\frac{2 r B}{\mu_0}\end{array}\)
Area \(A =\pi r^2\)
Substituting in equation (1)
Magnetic moment \(=\frac{2 r B}{\mu_0} \pi r^2\)
\(=\frac{2 \pi Br^3 }{\mu_0}\)
Magnetic field of circular loop
\(\begin{array}{l} B =\frac{\mu_0}{2} \frac{i}{r} \\ i=\frac{2 r B}{\mu_0}\end{array}\)
Area \(A =\pi r^2\)
Substituting in equation (1)
Magnetic moment \(=\frac{2 r B}{\mu_0} \pi r^2\)
\(=\frac{2 \pi Br^3 }{\mu_0}\)
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