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GUJCET · Physics · Wave Optics
The distance between two slits is 3 mm and screen is placed at 2 m distance. When blue-green light of wavelength 500 nm is used then distance between two fringes will be ?
- A 0.5 mm
- B 0.43 mm
- C 0.33 mm
- D 0.4 mm
Answer & Solution
Correct Answer
(C) 0.33 mm
Step-by-step Solution
Detailed explanation
(C) 0.33 mm
distance between fringes \(=\frac{\lambda D}{d}\)
\(\beta=\frac{\lambda D}{d}\)
\(\beta=\frac{5 \times 10^{-7} \times 2}{3 \times 10^{-3}}\)
\(\beta=3.3 \times 10^{-4}\)
\(\beta=0.33 \times 10^{-3}\)
\(\beta=0.33 \mathrm{~mm}\)
distance between fringes \(=\frac{\lambda D}{d}\)
\(\beta=\frac{\lambda D}{d}\)
\(\beta=\frac{5 \times 10^{-7} \times 2}{3 \times 10^{-3}}\)
\(\beta=3.3 \times 10^{-4}\)
\(\beta=0.33 \times 10^{-3}\)
\(\beta=0.33 \mathrm{~mm}\)
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