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GUJCET · Physics · Nuclei
A nucleus at rest splits into two nuclear parts having same density and radii in the ratio \(1: 2\). Their velocities are in the ratio \(\qquad\) .
- A \(2: 1\)
- B \(4: 1\)
- C \(6: 1\)
- D \(8: 1\)
Answer & Solution
Correct Answer
(D) \(8: 1\)
Step-by-step Solution
Detailed explanation
D.\(8: 1\)
According to law of conservation of momentum
\[
\begin{aligned}
\quad M_{1} v_{1}=M_{2} v_{2} \\
\therefore\left(9 \frac{4}{3} \pi r_{1}^{3}\right) v_{1}=\left(9 \frac{4}{3} \pi r_{2}^{3}\right) v_{2} \\
\therefore r_{1}^{3} v_{1}=r_{2}^{3} v_{2} \\
\therefore \frac{v_{1}}{v_{2}}=\left(\frac{r_{2}}{r_{1}}\right)^{3} \\
\therefore \frac{v_{1}}{v_{2}}=\left(\frac{2}{1}\right)^{3} \quad\left(\because \frac{r_{1}}{r_{2}}=\frac{1}{2}\right) \\
\therefore \frac{v_{1}}{v_{2}}=\frac{8}{1}
\end{aligned}
\]
According to law of conservation of momentum
\[
\begin{aligned}
\quad M_{1} v_{1}=M_{2} v_{2} \\
\therefore\left(9 \frac{4}{3} \pi r_{1}^{3}\right) v_{1}=\left(9 \frac{4}{3} \pi r_{2}^{3}\right) v_{2} \\
\therefore r_{1}^{3} v_{1}=r_{2}^{3} v_{2} \\
\therefore \frac{v_{1}}{v_{2}}=\left(\frac{r_{2}}{r_{1}}\right)^{3} \\
\therefore \frac{v_{1}}{v_{2}}=\left(\frac{2}{1}\right)^{3} \quad\left(\because \frac{r_{1}}{r_{2}}=\frac{1}{2}\right) \\
\therefore \frac{v_{1}}{v_{2}}=\frac{8}{1}
\end{aligned}
\]
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