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GUJCET · Physics · Electric Charges and Fields
A proton and a \(\alpha-\)particle are placed in uniform electric field. Accelerations produced in them are \(a_p\) and \(a_\alpha\) respectively. Then \(a_p\) : \(a_\alpha\) will be ___________.
- A 1 : 2
- B 4 : 1
- C 2 : 1
- D 1 : 4
Answer & Solution
Correct Answer
(C) 2 : 1
Step-by-step Solution
Detailed explanation
\(a = \frac{qE}{m}\) \(\frac{a_p}{a_\alpha} = \frac{q_p/m_p}{q_\alpha/m_\alpha} = \frac{e/m}{2e/4m} = \frac{e/m}{e/(2m)} = 2\)
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