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GUJCET · Physics · Magnetism And Matter

A domain in a ferromagnetic substance is in form of cube of side length \(2 \mu m\). It contains \(4 \times 10^{14}\) atoms and each atomic dipole has a moment of \(16 \times 10^{-24} Am ^2\), then the magnetization of the domain is then _________ .

  1. A \(8 \times 10^4\)
  2. B \(7.2 \times 10^4\)
  3. C \(3.6 \times 10^4\)
  4. D \(64 \times 10^4\)
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Correct Answer

(A) \(8 \times 10^4\)

Step-by-step Solution

Detailed explanation

A
Magnetization
\(M =\frac{n m}{V}\)
\(\begin{array}{l}\therefore \quad M=\frac{4 \times 10^{10} \times 16 \times 10^{-24}}{\left(2 \times 10^{-6}\right)^3} \\ \therefore \quad M=8 \times 10^4 Am ^{-1}\end{array}\)
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