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GUJCET · Physics · Dual Nature of Radiation and Matter

If the energy of photons corresponding to wavelength of \(6000 \)Å is \(3.2 \times 10-19 \mathrm{~J}\). The photon energy for wavelength \(4000\)Å will be _________ .

  1. A \(4.44 \times 10^{-19} \mathrm{~J}\)
  2. B \(2.22 \times 10^{-19} \mathrm{~J}\)
  3. C \(1.11 \times 10^{-19} \mathrm{~J}\)
  4. D \(4.80 \times 10^{-19} \mathrm{~J}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(4.80 \times 10^{-19} \mathrm{~J}\)

Step-by-step Solution

Detailed explanation

(D) \(4.80 \times 10^{-19} \mathrm{~J}\)
from \(\mathrm{E}=\frac{h c}{\lambda}\)
\(
\begin{aligned}
\frac{E_{2}}{E_{1}} & =\frac{\lambda_{1}}{\lambda_{2}} \\
\frac{E_{2}}{3.2 \times 10^{-19}} & =\frac{6 \times 10^{-7}}{4 \times 10^{-7}} \\
E_{2} & =\frac{6 \times 3.2 \times 10^{-19}}{4} \\
E_{2} & =4.80 \times 10^{-19} \mathrm{~J}
\end{aligned}
\)