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GUJCET · Physics · Electromagnetic Induction
A circular coil of area \(2 cm^2\) is placed in a magnetic field of 3 T perpendicularly the coil has 10 turns and \(5 \Omega\) resistance. Now the coil is removed from magnetic field in 0.2 s . The value of induced charge flowing through the coil is _________ .
- A 1.1 mC
- B 1.9 mC
- C 1.2 mC
- D zero
Answer & Solution
Correct Answer
(C) 1.2 mC
Step-by-step Solution
Detailed explanation
C
induced charge
\(\begin{array}{l}\Delta Q=\frac{\Delta \phi}{R} \\ \Delta Q=\frac{N A B}{R} \\ \Delta Q=\frac{10 \times 2 \times 10^{-4} \times 3}{5}\end{array}\)
\(\begin{array}{l}\Delta Q=12 \times 10^{-4} \\ \Delta Q=1.2 \times 10^{-3} C \\ \Delta Q=1.2 mC \end{array}\)
induced charge
\(\begin{array}{l}\Delta Q=\frac{\Delta \phi}{R} \\ \Delta Q=\frac{N A B}{R} \\ \Delta Q=\frac{10 \times 2 \times 10^{-4} \times 3}{5}\end{array}\)
\(\begin{array}{l}\Delta Q=12 \times 10^{-4} \\ \Delta Q=1.2 \times 10^{-3} C \\ \Delta Q=1.2 mC \end{array}\)
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