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GUJCET · Maths · Vector Algebra

The Angle between two consecutive side \(\vec{a}\) and \(\vec{b}\) of parallelogram is \(\frac{\pi}{6}, \vec{a}=(2,-2,1)\) and \(\vec{b}=2|\vec{a}|\), then area of parallelogram is _________ sq. units.

  1. A 9
  2. B 18
  3. C \(\frac{9}{2}\)
  4. D \(\frac{3}{4}\)
Verified Solution

Answer & Solution

Correct Answer

(A) 9

Step-by-step Solution

Detailed explanation

\(|\vec{a}| = \sqrt{2^2 + (-2)^2 + 1^2} = \sqrt{4+4+1} = \sqrt{9} = 3\) \(|\vec{b}| = 2|\vec{a}| = 2(3) = 6\)