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GUJCET · Maths · Vector Algebra
The Angle between two consecutive side \(\vec{a}\) and \(\vec{b}\) of parallelogram is \(\frac{\pi}{6}, \vec{a}=(2,-2,1)\) and \(\vec{b}=2|\vec{a}|\), then area of parallelogram is _________ sq. units.
- A 9
- B 18
- C \(\frac{9}{2}\)
- D \(\frac{3}{4}\)
Answer & Solution
Correct Answer
(A) 9
Step-by-step Solution
Detailed explanation
\(|\vec{a}| = \sqrt{2^2 + (-2)^2 + 1^2} = \sqrt{4+4+1} = \sqrt{9} = 3\) \(|\vec{b}| = 2|\vec{a}| = 2(3) = 6\)
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