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GUJCET · Maths · Three Dimensional Geometry
The cartesian equation line which is parallel to the line \(\frac{x+3}{3}=\frac{y-4}{5}=\frac{z+8}{6}\) and passing through the point \((1,-3,5)\) is \(\qquad\) .
- A \(\frac{x+3}{1}=\frac{y-4}{-3}=\frac{z+8}{5}\)
- B \(\frac{x-1}{3}=\frac{y+3}{5}=\frac{z-5}{6}\)
- C \(\frac{x+3}{-3}=\frac{y-4}{4}=\frac{z+8}{-8}\)
- D \(\frac{x-1}{-3}=\frac{y+3}{4}=\frac{z-5}{-8}\)
Answer & Solution
Correct Answer
(B) \(\frac{x-1}{3}=\frac{y+3}{5}=\frac{z-5}{6}\)
Step-by-step Solution
Detailed explanation
given point \( (1,-3,5) \) and aspect ratio \( (3,5,6) \). Equation of a line: \( \frac{x-1}{3}=\frac{y-(-3)}{5}=\frac{z-5}{6} \)
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