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GUJCET · Physics · Electromagnetic Induction
A magnetic flux of \(5 \mu Wb\) is linked with a coil when a current of 1 mA flows through it. Calculate the self inductance of the coil.
- A \(5 \times 10^{-3} H\)
- B \(5 \times 10^3 H\)
- C \(2 \times 10^{-2} H\)
- D \(2 \times 10^2 H\)
Answer & Solution
Correct Answer
(A) \(5 \times 10^{-3} H\)
Step-by-step Solution
Detailed explanation
A
self inductance \(L =\frac{\phi}{ I }\)
\(\begin{array}{l}=\frac{5 \times 10^{-6}}{1 \times 10^{-3}} \\ =5 \times 10^{-3} H \end{array}\)
self inductance \(L =\frac{\phi}{ I }\)
\(\begin{array}{l}=\frac{5 \times 10^{-6}}{1 \times 10^{-3}} \\ =5 \times 10^{-3} H \end{array}\)
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