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GUJCET · Maths · Inverse Trigonometric Functions
If \(\cos \left(\cos ^{-1} \frac{\sqrt{3}}{2}+\sin ^{-1} x\right)=1\), then find value of \(x\).
- A 0
- B \(-\frac{1}{2}\)
- C \(-\frac{\sqrt{3}}{2}\)
- D \(\frac{\sqrt{3}}{2}\)
Answer & Solution
Correct Answer
(B) \(-\frac{1}{2}\)
Step-by-step Solution
Detailed explanation
\(\cos ^{-1} \frac{\sqrt{3}}{2}+\sin ^{-1} x = \cos^{-1}(1)\) \(\frac{\pi}{6}+\sin ^{-1} x = 0\)
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