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GUJCET · Maths · Inverse Trigonometric Functions

If \(\cos \left(\cos ^{-1} \frac{\sqrt{3}}{2}+\sin ^{-1} x\right)=1\), then find value of \(x\).

  1. A 0
  2. B \(-\frac{1}{2}\)
  3. C \(-\frac{\sqrt{3}}{2}\)
  4. D \(\frac{\sqrt{3}}{2}\)
Verified Solution

Answer & Solution

Correct Answer

(B) \(-\frac{1}{2}\)

Step-by-step Solution

Detailed explanation

\(\cos ^{-1} \frac{\sqrt{3}}{2}+\sin ^{-1} x = \cos^{-1}(1)\) \(\frac{\pi}{6}+\sin ^{-1} x = 0\)