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GUJCET · Chemistry · Electrochemistry

Calculate the equilibrium constant of the following reaction:
\(\mathrm{Cu}_{(\mathrm{s})}+2 \mathrm{Ag}_{(\mathrm{eq})}^{+} \rightarrow \mathrm{Cu}_{(\mathrm{aq})}^{2+}+2 \mathrm{Ag}_{(\mathrm{s})} \mathrm{E}_{(\text {cell })}^{\circ}=0.46 \mathrm{~V}\)

  1. A \(3.92 \times 10^{14}\)
  2. B \(4.92 \times 10^{13}\)
  3. C \(4.92 \times 10^{14}\)
  4. D \(3.92 \times 10^{15}\)
Verified Solution

Answer & Solution

Correct Answer

(D) \(3.92 \times 10^{15}\)

Step-by-step Solution

Detailed explanation

\(n = 2\) \(E^\circ_{\text{cell}} = \frac{0.0257}{n} \ln K\)