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GUJCET · Chemistry · Electrochemistry
Calculate the equilibrium constant of the following reaction:
\(\mathrm{Cu}_{(\mathrm{s})}+2 \mathrm{Ag}_{(\mathrm{eq})}^{+} \rightarrow \mathrm{Cu}_{(\mathrm{aq})}^{2+}+2 \mathrm{Ag}_{(\mathrm{s})} \mathrm{E}_{(\text {cell })}^{\circ}=0.46 \mathrm{~V}\)
- A \(3.92 \times 10^{14}\)
- B \(4.92 \times 10^{13}\)
- C \(4.92 \times 10^{14}\)
- D \(3.92 \times 10^{15}\)
Answer & Solution
Correct Answer
(D) \(3.92 \times 10^{15}\)
Step-by-step Solution
Detailed explanation
\(n = 2\) \(E^\circ_{\text{cell}} = \frac{0.0257}{n} \ln K\)
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