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GUJCET · Maths · Integrals
\(\int_0^{\pi / 4} \sqrt{1+\sin 2 x} d x=\) ___________ .
- A 2
- B 1
- C \(\frac{1}{2}\)
- D 0
Answer & Solution
Correct Answer
(B) 1
Step-by-step Solution
Detailed explanation
\(\int_0^{\pi / 4} \sqrt{1+\sin 2 x} d x = \int_0^{\pi / 4} \sqrt{(\sin x+\cos x)^2} d x\) \(= \int_0^{\pi / 4} (\sin x+\cos x) d x\)
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