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GUJCET · Maths · Application of Integrals
Area lying in the first quadrant and bounded by ellipse \(4x^2 + 9y^2 = 144\) is ________.
- A \(12 \pi\)
- B \(24 \pi\)
- C \(8 \pi\)
- D \(6 \pi\)
Answer & Solution
Correct Answer
(D) \(6 \pi\)
Step-by-step Solution
Detailed explanation
\( \frac{4x^2}{144} + \frac{9y^2}{144} = 1 \Rightarrow \frac{x^2}{36} + \frac{y^2}{16} = 1 \) \( a = \sqrt{36} = 6 \), \( b = \sqrt{16} = 4 \)
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