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GUJCET · Maths · Vector Algebra
The area of parallelogram whose adjacent sides are \(\vec{a}=2 \hat{i}+3 \hat{j}+4 \hat{k}\) and \(\vec{b}=-\hat{j}-2 \hat{k}\) is _________ sq. units.
- A \(2 \sqrt{6}\)
- B \(\sqrt{6}\)
- C 24
- D \(2 \sqrt{3}\)
Answer & Solution
Correct Answer
(A) \(2 \sqrt{6}\)
Step-by-step Solution
Detailed explanation
\(\vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 2 & 3 & 4 \\ 0 & -1 & -2 \end{vmatrix}\) \(= \hat{i}(-6+4) - \hat{j}(-4-0) + \hat{k}(-2-0)\)
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