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GUJCET · Maths · Vector Algebra

The area of parallelogram whose adjacent sides are \(\vec{a}=2 \hat{i}+3 \hat{j}+4 \hat{k}\) and \(\vec{b}=-\hat{j}-2 \hat{k}\) is _________ sq. units.

  1. A \(2 \sqrt{6}\)
  2. B \(\sqrt{6}\)
  3. C 24
  4. D \(2 \sqrt{3}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(2 \sqrt{6}\)

Step-by-step Solution

Detailed explanation

\(\vec{a} \times \vec{b} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 2 & 3 & 4 \\ 0 & -1 & -2 \end{vmatrix}\) \(= \hat{i}(-6+4) - \hat{j}(-4-0) + \hat{k}(-2-0)\)