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GUJCET · Maths · Continuity and Differentiability
\(\begin{array}{l}\frac{d}{d x}\left(3 \cos \left(\frac{\pi}{6}+x^{\circ}\right)-4 \cos ^3\left(\frac{\pi}{6}+x^{\circ}\right)\right) = \end{array}\) _________
- A \(\cos 3 x^{\circ}\)
- B \(\frac{\pi}{60} \sin \left(3 x^{\circ}\right)\)
- C \(\frac{\pi}{60} \cos \left(3 x^{\circ}\right)\)
- D \(-\frac{\pi}{60} \sin \left(3 x^{\circ}\right)\)
Answer & Solution
Correct Answer
(C) \(\frac{\pi}{60} \cos \left(3 x^{\circ}\right)\)
Step-by-step Solution
Detailed explanation
\(\frac{d}{d x}\left(3 \cos \left(\frac{\pi}{6}+x^{\circ}\right)-4 \cos ^3\left(\frac{\pi}{6}+x^{\circ}\right)\right) = \frac{d}{d x}\left(-\left(4 \cos ^3\left(\frac{\pi}{6}+x^{\circ}\right)-3 \cos \left(\frac{\pi}{6}+x^{\circ}\right)\right)\right)\) \(= \frac{d}{d x}\left(-\cos\left(3\left(\frac{\pi}{6}+x^{\circ}\right)\right)\right)\)
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