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GUJCET · Chemistry · Coordination Compounds
How many electrons are present in 3d orbital of tetrahedral \(K _2\left[ NiCl _4\right]\) complex.
- A 10 electrons
- B 8 electrons
- C 6 electrons
- D 7 electrons
Answer & Solution
Correct Answer
(B) 8 electrons
Step-by-step Solution
Detailed explanation
B
\(\begin{array}{l} K _2\left[ NiCl _4\right] \rightarrow 2 K^{+}+\left[ NiCl _4\right]^{2-} \\ Ni ^{2+}:-[ Ar ] 3 d^8 4 s\end{array}\)
\(\begin{array}{l} K _2\left[ NiCl _4\right] \rightarrow 2 K^{+}+\left[ NiCl _4\right]^{2-} \\ Ni ^{2+}:-[ Ar ] 3 d^8 4 s\end{array}\)
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