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GUJCET · Chemistry · Chemical Kinetics

At 298 K temperature the activation energy for the reaction \(x_2+y_2 \rightarrow 2 x y+20 kJ\) is 15 kJ .what will be the activation energy for the reaction \(2 x y \rightarrow x_2+y_2\) ?

  1. A -15 kJ
  2. B +35 kJ
  3. C -5 kJ
  4. D -35 kJ
Verified Solution

Answer & Solution

Correct Answer

(B) +35 kJ

Step-by-step Solution

Detailed explanation

B
\(\begin{array}{l}\Delta_R H=\text { activation energy of forward reaction } \\ \quad-\text { activation energy of backward reaction. } \\ \Rightarrow-20=15-x \\ \text { So, }+35 kJ\end{array}\)