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GUJCET · Chemistry · Chemical Kinetics
At 298 K temperature the activation energy for the reaction \(x_2+y_2 \rightarrow 2 x y+20 kJ\) is 15 kJ .what will be the activation energy for the reaction \(2 x y \rightarrow x_2+y_2\) ?
- A -15 kJ
- B +35 kJ
- C -5 kJ
- D -35 kJ
Answer & Solution
Correct Answer
(B) +35 kJ
Step-by-step Solution
Detailed explanation
B
\(\begin{array}{l}\Delta_R H=\text { activation energy of forward reaction } \\ \quad-\text { activation energy of backward reaction. } \\ \Rightarrow-20=15-x \\ \text { So, }+35 kJ\end{array}\)
\(\begin{array}{l}\Delta_R H=\text { activation energy of forward reaction } \\ \quad-\text { activation energy of backward reaction. } \\ \Rightarrow-20=15-x \\ \text { So, }+35 kJ\end{array}\)
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