Two different electrolytic cells filled with molten \(Cu \left( NO _3\right)_2\) and molten \(Al \left( NO _3\right)_3\) respectively are connected in series. When electricity is passed 2.7 gram Al is deposited on electrode. Calculate the weight of Cu deposited on cathode. [Cu 63.5; Al 27.0 gram \(mol ^{-1}\) ]

A 190.5 gram
B 9.525 gram
C 63.5 gram
D 31.75 gram

Verified Solution

Answer & Solution

Correct Answer

(B) 9.525 gram

Step-by-step Solution

Detailed explanation

B
\(\begin{aligned} \frac{\text { Wt of Cu }}{\text { Wt of Al }} & =\frac{\text { Eq. Wt of Cu }}{\text { Eq. Wt of Al }} \\ \frac{\text { Wt of Cu }}{2.7} & =\frac{\frac{63.5}{2}}{\frac{27}{3}} \\ & =\frac{31.75 \times 2.7}{9} \\ & =9.525 gm \end{aligned}\)

Apply the relevant identity from the chapter and substitute the values established in the previous step, keeping the original constraint in view.

Use the simplified expression to isolate the unknown, then plug the result back into the question setup to confirm the working is internally consistent.

Cross-check against a boundary or limiting case. Both the dimensional balance and the qualitative behaviour at the extreme should agree with the candidate answer.

Combine the steps above to identify the correct option. The remaining choices each fail at least one of the consistency, dimensional, or boundary checks.

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