COMEDK · Physics · 30. Semiconductors
An LED is constructed from a \(p\)-\(n\) junction diode using GaAsP. The energy gap is \(1.9 \mathrm{~eV}\). The wavelength of the light emitted will be equal to
- A \(654 ~\mathop A\limits^o\)
- B \(654 \mathrm{~nm}\)
- C \(654 \times 10^{-11} \mathrm{~m}\)
- D \(10.4 \times 10^{-26} \mathrm{~m}\)
Answer & Solution
Correct Answer
(B) \(654 \mathrm{~nm}\)
Step-by-step Solution
Detailed explanation
The energy of the emitted photon is given by the energy gap \(E_g\) of the semiconductor material. \(E_g = 1.9 \text{ eV} = 1.9 \times 1.6 \times 10^{-19} \text{ J} = 3.04 \times 10^{-19} \text{ J}\) The relationship between the energy of a photon and its wavelength \(\lambda\)…
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