COMEDK · Physics · 3. Motion In One Dimension
A stone is dropped from a height \(h\). It hits the ground with a certain momentum ' \(p\) '. If the same stone is dropped from a different height h' such that percentage change in momentum is \(41.4 \%\), then the height from which the stone is dropped is \(\mathrm{h}^\prime=x \mathrm{~h}\), where \(x\) is:
- A \(6\)
- B \(3\)
- C \(4\)
- D \(2\)
Answer & Solution
Correct Answer
(D) \(2\)
Step-by-step Solution
Detailed explanation
The momentum \(p\) of a stone dropped from height \(h\) is given by \(p = mv\), where \(v = \sqrt{2gh}\). Thus, \(p = m\sqrt{2gh}\), which implies \(p \propto \sqrt{h}\). Let \(p\) be the initial momentum and \(p'\) be the final momentum. The percentage change in momentum is…
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