COMEDK · Physics · 15. Oscillations
An object of mass 10g executes SHM along the \(x\)-axis with frequency of \(\left(\dfrac{10}{\pi}\right)\)Hz. At the point \(x = 2\ cm\) the object has KE 1.2 J and PE 0.4 J. The amplitude of oscillation is
- A \(8\ \text{cm}\)
- B \(6\ \text{cm}\)
- C \(2\ \text{cm}\)
- D \(4\ \text{cm}\)
Answer & Solution
Correct Answer
(D) \(4\ \text{cm}\)
Step-by-step Solution
Detailed explanation
Given, Kinetic Energy (\(KE\)) = \(1.2\) J and Potential Energy (\(PE\)) = \(0.4\) J at displacement \(x = 2\) cm. The total energy (\(E\)) of the object executing SHM is the sum of its kinetic and potential energies: \(E = KE + PE = 1.2 + 0.4 = 1.6\) J In simple harmonic…
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