COMEDK · Physics · 9. Gravitation
A body is projected vertically upwards from the surface of earth with a velocity 'v' to reach a height of 10R, where R is the radius of the earth, then v is
- A \(\sqrt{\dfrac{20gR}{11}}\)
- B \(\sqrt{\dfrac{10gR}{11}}\)
- C \(\sqrt{\dfrac{21gR}{11}}\)
- D \(\sqrt{\dfrac{21gR}{10}}\)
Answer & Solution
Correct Answer
(A) \(\sqrt{\dfrac{20gR}{11}}\)
Step-by-step Solution
Detailed explanation
By conservation of mechanical energy: \(K_i + U_i = K_f + U_f\) \(\dfrac{1}{2}mv^2 - \dfrac{GMm}{R} = 0 - \dfrac{GMm}{R + 10R}\) \(\dfrac{1}{2}mv^2 = \dfrac{GMm}{R} - \dfrac{GMm}{11R}\) \(\dfrac{1}{2}v^2 = \dfrac{10GM}{11R}\) \(v^2 = \dfrac{20GM}{11R}\) Using…
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