AP EAMCET · PHYSICS · Dual Nature of Matter
When light of wavelength \(\lambda\) incidents on a photosensitive material, photoelectrons are emitted. If the wavelength of the incident light is reduced by \(50 \%\), the maximum kinetic energy of the emitted photoelectrons becomes 3 times the initial maximum kinetic energy. The work function of the material is
( \(\mathrm{h}\) - Planck's constant, \(\mathrm{c}-\) Speed of light in vacuum)
- A \(\frac{\mathrm{hc}}{\lambda}\)
- B \(\frac{\mathrm{hc}}{2 \lambda}\)
- C \(\frac{2 \mathrm{hc}}{\lambda}\)
- D \(\frac{\mathrm{hc}}{3 \lambda}\)
Answer & Solution
Correct Answer
(B) \(\frac{\mathrm{hc}}{2 \lambda}\)
Step-by-step Solution
Detailed explanation
From the photoelectric equation \(\frac{\mathrm{hc}}{\lambda}=\mathrm{E}+\phi...(i)\) When \(\lambda^{\prime}=0.5 \lambda=\frac{\lambda}{2}\) Maximum Kinetic Energy, \(\mathrm{E}^{\prime}=3 \mathrm{E}\) \(\frac{2 \mathrm{hc}}{\lambda}=3 \mathrm{E}+\phi... (ii)\) Solving equation…
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