AP EAMCET · PHYSICS · Oscillations
The potential energy of a particle of mass 10 g as a function of displacement \(x\) is \(\left(50 x^2+100\right) \mathrm{J}\). The frequency of oscillation is
- A \(\frac{10}{\pi} s^{-1}\)
- B \(\frac{5}{\pi} s^{-1}\)
- C \(\frac{100}{\pi} s^{-1}\)
- D \(\frac{50}{\pi} s^{-1}\)
Answer & Solution
Correct Answer
(D) \(\frac{50}{\pi} s^{-1}\)
Step-by-step Solution
Detailed explanation
\(\mathrm{m}=10 \mathrm{~gm} =10 \times 10^{-3} \mathrm{~kg}, \mathrm{U}=\left(50 \mathrm{x}^2+100\right) \mathrm{J}\) \(\therefore\) Restoring force, \(\mathrm{F}=-\frac{\mathrm{du}}{\mathrm{dx}}\)…
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