AP EAMCET · PHYSICS · Electrostatics
Two charges \(+\mathrm{q}\) and \(-\mathrm{q}\), each \(1 \mu \mathrm{C}\) are arranged as shown in the figure. If \(x=2 \mathrm{~cm}\) and \(y=3 \mathrm{~cm}\) then potential difference \(\left(V_A-V_B\right)\) is
- A \(5.4 \times 10^2 \mathrm{~V}\)
- B \(5.4 \times 10^5 \mathrm{~V}\)
- C \(5.2 \times 10^2 \mathrm{~V}\)
- D \(2.7 \times 10^5 \mathrm{~V}\)
Answer & Solution
Correct Answer
(D) \(2.7 \times 10^5 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
Distance between two charge, \(d=2 x+y\) \[ =2 \times 2+3=7 \times 10^{-2} \mathrm{~m} \] Potential at \(A, V_A=\frac{1}{4 \pi \epsilon_0} \frac{q}{d}\) \[ =9 \times 10^9 \times \frac{1 \times 10^{-6}}{7 \times 10^{-2}} \] Potential at…
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