AP EAMCET · PHYSICS · Kinetic Theory of Gases
\(50 \mathrm{~g}\) of copper is heated to increase its temperature by \(10^{\circ} \mathrm{C}\). If the same quantity of heat is given to \(10 \mathrm{~g}\) of water, the rise in temperature is (specific heat of \(\mathrm{Cu}=420 \mathrm{Jkg}^{-10} \mathrm{C}^{-1}\) and specific heat of water is \(4200 \mathrm{Jkg}^{-10} \mathrm{C}^{-1}\) )
- A \(6^{\circ} \mathrm{C}\)
- B \(10^{\circ} \mathrm{C}\)
- C \(5^{\circ} \mathrm{C}\)
- D \(15^{\circ} \mathrm{C}\)
Answer & Solution
Correct Answer
(C) \(5^{\circ} \mathrm{C}\)
Step-by-step Solution
Detailed explanation
Given, Since, the same amount of heat supplied to copper and water \(Q_1=Q_2 \Rightarrow m_1 s_1 \Delta t_1=m_2 s_2 \Delta t_2\) Substituting the value, we get \(50 \times 420 \times 10=10 \times 4200 \times \Delta t_2\) \(\Delta t_2=5^{\circ} \mathrm{C}\)
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