AP EAMCET · PHYSICS · Electrostatics
Two charges 5 nC and -2 nC are placed at points \((5 \mathrm{~cm}, 0,0)\) and \((23 \mathrm{~cm}, 0,0)\) in a region of space where there is no other external field. The electrostatic potential energy of this charge system is
- A \(10 \times 10^{-7} \mathrm{~J}\)
- B \(5 \times 10^{-7} \mathrm{~J}\)
- C \(15 \times 10^{-7} \mathrm{~J}\)
- D \(25 \times 10^{-7} \mathrm{~J}\)
Answer & Solution
Correct Answer
(B) \(5 \times 10^{-7} \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \mathrm{q}_1=5 \mathrm{nC}=5 \times 10^{-9} \mathrm{C}, \mathrm{q}_2=-2 \mathrm{nC}=-2 \times 10^{-9} \mathrm{C} \\ & \mathrm{r}=(23-5)=18 \mathrm{~cm}=18 \times 10^{-2} \mathrm{~m} \end{aligned}\) \(\therefore \quad\) The electrostatic potential energy of…
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