AP EAMCET · PHYSICS · Center of Mass Momentum and Collision
Four identical spheres each of radius \(10 \mathrm{~cm}\) and equal mass \(1 \mathrm{~kg}\) each are placed on horizontal surface touching each other, so that their centre are located at the vertices of a square of side \(20 \mathrm{~cm}\). What is the distance of their centre of mass from the centre of either sphere?
- A \(20 \sqrt{2}\)
- B \(30 \sqrt{2}\)
- C \(10 \sqrt{2}\)
- D \(40 \sqrt{2}\)
Answer & Solution
Correct Answer
(C) \(10 \sqrt{2}\)
Step-by-step Solution
Detailed explanation
The given situation is shown in the figure, \(A B=B C=C D=D A=20 \mathrm{~cm}\) Since, all spheres are identical with mass \(1 \mathrm{~kg}\) and radius \(10 \mathrm{~cm}\) each, hence according to figure, it is clear that all spheres are symmetrically arranged, hence centre of…
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