AP EAMCET · PHYSICS · Work Power Energy
When a body moves in a circular path, no work is done by the force, since
- A there is no net force
- B there is no displacement
- C force is always away from the centre
- D force and displacement are perpendicular to each other
Answer & Solution
Correct Answer
(D) force and displacement are perpendicular to each other
Step-by-step Solution
Detailed explanation
When a body moves in a circular path, then centripetal force is always directed towards centre of circular path. Hence, centripetal force and displacement (directed tangentially) are perpendicular to each other. \(\therefore\) Work done…
See the Complete Solution
Get step-by-step explanations for this and 2.5 Lakh+ more JEE, NEET & CET questions.
- Unlock all solutions
- Practice the full chapter
- Track accuracy across PYQs
4.8 rated on Google Play · 14,000+ reviews
More questions from PHYSICS
- A cylindrical rod made of aluminum has length 1 meter and diameter of \(10 \mathrm{~cm}\). The rod is subjected to a tensile force of \(100 \mathrm{kN}\). The elongation in the rod is
(Young's modulus of aluminum \(=70 \mathrm{GPa}\) )AP EAMCET 2023 Medium - Bernoulli's theorem is based on the conservation ofAP EAMCET 2021 Easy
- The condition \(d Q=d W\) holds good in which of the following ?AP EAMCET 2020 Easy
- The current and emf through an inductance differ by phase byAP EAMCET 2021 Easy
- The coefficient of restitution for a perfect elastic collision isAP EAMCET 2021 Easy
- A metal loop of area \(10 \mathrm{~cm}^2\) is placed in a region such that its area vector points along \(\hat{\mathrm{k}}\). The region contains a uniform magnetic field of magnitude \(1.73 \mathrm{~T}\) that points in the direction \(\hat{i}+\hat{j}+\hat{k}\). When the magnetic field is switched off, the field decreases to zero at a steady rate in \(10 \mathrm{~s}\), then the magnitude of emf induced in the loop isAP EAMCET 2022 Medium
More PYQs from AP EAMCET
- The sides of a \(\triangle A B C\) are given by \(a=3, b=5\) and \(c=3\). Then, \(\cos A=\)AP EAMCET 2022 Easy
- \(\operatorname{Tan}^{-1} \frac{\sqrt{8-2 \sqrt{15}}}{\sqrt{15}+1}+\operatorname{Tan}^{-1} \frac{1}{\sqrt{5}}=\)AP EAMCET 2025 Medium
- Which transition metal does not form 'MO' type oxide? ( \(\mathrm{M}=\) transition metal)AP EAMCET 2024 Medium
- A particle is executing simple harmonic motion with amplitude \(A\). The ratio of the kinetic energies of the particle when it is at displacements of \(\frac{A}{4}\) and \(\frac{A}{2}\) from the mean position isAP EAMCET 2025 Medium
- Which among the following can be explained by adsorption theory?AP EAMCET 2020 Easy
- Which is the most covalent?AP EAMCET 2021 Medium