AP EAMCET · PHYSICS · Oscillations
Under the action of a force \(F=-75 y\) where \(F\) is in Newton and \(y\) is in meters, an object of mass \(3 \mathrm{~kg}\) executes simple harmonic motion. If the velocity of the object at the mean position is \(2.5 \mathrm{~ms}^{-1}\), the maximum acceleration of the object is
- A \(5 \mathrm{~ms}^{-2}\)
- B \(7.5 \mathrm{~ms}^{-2}\)
- C \(10 \mathrm{~ms}^{-2}\)
- D \(12.5 \mathrm{~ms}^{-2}\)
Answer & Solution
Correct Answer
(D) \(12.5 \mathrm{~ms}^{-2}\)
Step-by-step Solution
Detailed explanation
Action of force, \(F=-75 y\) Compair with \(\mathrm{F}=-\mathrm{k} \mathrm{y}\) \(\mathrm{k}=75 \mathrm{~N} / \mathrm{m}\) Velocity of the object, \(v=2.5 \mathrm{~m} / \mathrm{s}\) \(\mathrm{V}_{\max }=\mathrm{A} \omega\)…
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