AP EAMCET · Maths · Pair of Lines
The value of ' \(k\) ' for which the equation \(x^2-4 x y-y^2+6 x+2 y+k=0\) represents a pair of straight lines is equal to ........
- A \(\frac{4}{5}\)
- B \(\frac{-3}{5}\)
- C \(\frac{-4}{5}\)
- D \(\frac{3}{5}\)
Answer & Solution
Correct Answer
(C) \(\frac{-4}{5}\)
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & x^2-4 x y-y^2+6 x+2 y+k=0 \quad \ldots (i) \\ & a=1,2 h=-4, b=-1,2 g=6,2 f=2, c=k \end{aligned}\) Eq. (i) Represents a pair of straight line…
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