AP EAMCET · PHYSICS · Thermal Properties of Matter
A hunter fired a metallic bullet of mass \(m \mathrm{~kg}\) from a gun towards an obstacle and it just melts when it is stopped by the obstacle. The initial temperature of the bullet is \(300 \mathrm{~K}\). If \(\frac{1}{4}\) th of heat is absorbed by the obstacle, then the minimum velocity of the bullet is (Melting point of bullet \(=600 \mathrm{~K}\), Specific heat of bullet \(=0.03 \mathrm{cal} \mathrm{g}^{-1}{ }^{\circ} \mathrm{C}^{-1}\), Latent heat of fusion of bullet \(=6 \mathrm{cal} \mathrm{g}^{-1}\) )
- A \(410 \mathrm{~ms}^{-1}\)
- B \(260 \mathrm{~ms}^{-1}\)
- C \(460 \mathrm{~ms}^{-1}\)
- D \(310 \mathrm{~ms}^{-1}\)
Answer & Solution
Correct Answer
(A) \(410 \mathrm{~ms}^{-1}\)
Step-by-step Solution
Detailed explanation
As per question \(\frac{1}{4}\) th of heat is absorbed by the obstacle so, \(\frac{3}{4}\left(\frac{1}{2} m v^2\right)=m s \Delta \theta+m L\)…
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