AP EAMCET · PHYSICS · Oscillations
Ratio of maximum acceleration to the maximum velocity of a simple harmonic oscillator is
- A \(\omega\)
- B \(\frac{\omega}{2}\)
- C \(\omega^2\)
- D \(2 \omega\)
Answer & Solution
Correct Answer
(A) \(\omega\)
Step-by-step Solution
Detailed explanation
For SHM, we know that, Maximum acceleration, \(\left|a_{\max }\right|=\omega^2 A\) Maximum velocity, \(\left|v_{\max }\right|=\omega A\) where, \(\omega=\) angular velocity/frequency \(A=\) amplitude \(\therefore\) According to question, the ratio is…
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