AP EAMCET · PHYSICS · Work Power Energy
In the arrangement shown in the figure, work done by the string on the block of mass \(0.36 \mathrm{~kg}\) during the first second after the blocks are released from state of rest is (Ignore friction and mass of the string.)
(Acceleration due to gravity, \(g\) \(=10 \mathrm{~ms}^{-2}\))
- A \(8 \mathrm{~J}\)
- B \(4 \mathrm{~J}\)
- C \(12 \mathrm{~J}\)
- D \(2 \mathrm{~J}\)
Answer & Solution
Correct Answer
(A) \(8 \mathrm{~J}\)
Step-by-step Solution
Detailed explanation
According to the question, Given, mass of block \(1, m_1=0.36 \mathrm{~kg}\) mass of block \(2, m_2=0.72 \mathrm{~kg}\) and acceleration due to gravity, \(g=10 \mathrm{~m} / \mathrm{s}^2\) Now, Dynamic equation of block \(m_1\left(m_2 > m_1\right)\).…
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