AP EAMCET · PHYSICS · Mechanical Properties of Solids
Two springs A and B fixed at the top and are stretched by \(8 \mathrm{~cm}\) and \(16 \mathrm{~cm}\) respectively, when loads of \(20 \mathrm{~N}\) and \(10 \mathrm{~N}\) are suspended at the lower ends. The ratio of the spring constants of the springs \(A\) and \(B\) is
- A \(1: 1\)
- B \(2: 1\)
- C \(3: 1\)
- D \(4: 1\)
Answer & Solution
Correct Answer
(D) \(4: 1\)
Step-by-step Solution
Detailed explanation
Spring constant, \(K=\frac{F}{x}\) Given, \(\mathrm{F}_{\mathrm{A}}=20 \mathrm{~N}, \mathrm{~F}_{\mathrm{B}}=10 \mathrm{~N}, \mathrm{x}_{\mathrm{A}}=8 \mathrm{~cm}\) and \(\mathrm{x}_{\mathrm{B}}=16 \mathrm{~cm}\)…
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