AP EAMCET · PHYSICS · Mechanical Properties of Fluids
Two soap bubbles combine to form a single bubble. In this process, the change in volume and surface area are respectively \(V\) and \(A\). If \(P\) is the atmospheric pressure, and \(T\) is the surface tension of the soap solution, the following relation is true :
- A \(4 P V+3 T A=0\)
- B \(3 P V-4 T A=0\)
- C \(4 P V-3 T A=0\)
- D \(3 P V+4 T A=0\)
Answer & Solution
Correct Answer
(D) \(3 P V+4 T A=0\)
Step-by-step Solution
Detailed explanation
Let radii of two soap bubbles are \(a\) and \(b\) respectively and radius of single larger bubble is \(c\). As excess pressure for a soap bubble is \(\frac{4 T}{r}\) and external pressure \(P\). \(P_i=P+\frac{4 T}{r}\) So, \(\quad P_a=P+\frac{4 T}{a}, P_b=P+\frac{4 T}{b}\) and…
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