AP EAMCET · PHYSICS · Current Electricity
A galvanometer, having a resistance of \(50 \Omega\), gives a full scale deflection for a current of 0.05 A. The length in metre of a resistance wire of area of cross-section \(2.97 \times 10^{-2} \mathrm{~cm}^2\) that can be used to convert the galvanometer into an ammeter which can read a maximum of 5 A current is :
(Specific resistance of the wire\(\left.=5 \times 10^{-7} \Omega-\mathrm{m}\right)\)
- A 9
- B 6
- C 3
- D 1.5
Answer & Solution
Correct Answer
(C) 3
Step-by-step Solution
Detailed explanation
Resistance of galvanometer, \(G=50 \Omega\) Full scale current, \(i_g=0.05\) \(A=2.97 \times 10^{-2} \mathrm{~cm}^2\) \(=2.97 \times 10^{-2} \times 10^{-4} \mathrm{~m}^2\) \(=2.97 \times 10^{-6} \mathrm{~m}^2\) \(i=5 \mathrm{~A}\) \(\rho=5 \times 10^{-7} \Omega-\mathrm{m}\)…
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