AP EAMCET · Maths · Complex Number
. If \(\alpha, \beta\) are the roots of the equation \(x^2-2 x+4=0\), then \(\alpha^n+\beta^n=\ldots \ldots\) \(x \cos \left(\frac{n \pi}{3}\right)\) for any \(n \in \mathbf{N}\)
- A \(2^n\)
- B \(2^{n+1}\)
- C \(2^{n-1}\)
- D \(2^{n-2}\)
Answer & Solution
Correct Answer
(B) \(2^{n+1}\)
Step-by-step Solution
Detailed explanation
Given quadratic equation \(x^2-2 x+4=0\) having roots \(\alpha\) and \(\beta\). So, \(\alpha, \beta=\frac{2 \pm \sqrt{4-16}}{2}=\frac{2 \pm 2 \sqrt{3} i}{2}=1 \pm \sqrt{3 i}\)…
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