AP EAMCET · PHYSICS · Wave Optics
Two slits separated by \(0.5 \mathrm{~mm}\) are illuminated by light of wavelength \(500 \mathrm{~nm}\). The screen is at a distance of \(120 \mathrm{~cm}\) from the slits. The phase difference between the interfering waves at a point \(3 \mathrm{~mm}\) on the screen from the central bright fringe is ........... .
- A \(5 \pi\)
- B \(\pi\)
- C \(3 \pi\)
- D \(7 \pi\)
Answer & Solution
Correct Answer
(A) \(5 \pi\)
Step-by-step Solution
Detailed explanation
Given, \[ \begin{aligned} & \mathrm{d}=0.5 \times 10^{-9} \mathrm{~m} \text { and } \gamma=3 \times 10^{-3} \mathrm{~mm} \\ & \lambda=500 \times 10^{-9} \mathrm{~m} \\ & D=120 \mathrm{~cm}=120 \times 10^{-2} \mathrm{~m} \\ & \gamma=\frac{\Delta x D}{d} \end{aligned} \]…
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