AP EAMCET · PHYSICS · Alternating Current
The coils of a step-down transformer have 500 and 5000 turns. In the primary coil an \(\mathrm{AC}\) current of \(4 \mathrm{~A}\) at \(2200 \mathrm{~V}\) is sent. The value of the current and potential difference in the secondary coil is
- A \(20 \mathrm{~A}, 220 \mathrm{~V}\)
- B \(0.4 \mathrm{~A}, 22000 \mathrm{~V}\)
- C \(40 \mathrm{~A}, 220 \mathrm{~V}\)
- D \(40 \mathrm{~A}, 22000 \mathrm{~V}\)
Answer & Solution
Correct Answer
(C) \(40 \mathrm{~A}, 220 \mathrm{~V}\)
Step-by-step Solution
Detailed explanation
For a step-down transformer, \(\begin{aligned} N_P & =5000, N_S=500 \\ I_P & =4 \mathrm{~A}, V_P=2200 \mathrm{~V} \end{aligned}\) For a transformer, we know that…
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