AP EAMCET · PHYSICS · Oscillations
A body of mass \(\mathrm{I} \mathrm{kg}\) is suspended from a spring of negligible mass. Another body of mass \(500 \mathrm{~g}\) moving vertically upwards hits the suspended body with a velocity of \(3 \mathrm{~ms}^{-1}\) and gets embedded in it. If the frequency of oscillation of the system of the two bodies after collision is \(\frac{10}{\pi} \mathrm{Hz}\), the amplitude of the motion and the spring constant are respectively,
- A \(5 \mathrm{~cm}, 300 \mathrm{Nm}^{-1}\)
- B \(10 \mathrm{~cm}, 300 \mathrm{Nm}^{-1}\)
- C \(10 \mathrm{~cm}, 600 \mathrm{Nm}^{-1}\)
- D \(5 \mathrm{~cm}, 600 \mathrm{Nm}^{-1}\)
Answer & Solution
Correct Answer
(D) \(5 \mathrm{~cm}, 600 \mathrm{Nm}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, mass of body, \(M=1 \mathrm{~kg}\), frequency of oscillation, \(f=\frac{10}{\pi} \mathrm{Hz}\), mass of hitting body, \(m=0.5 \mathrm{~kg}\) and speed of body, \(v=3 \mathrm{~ms}^{-1}\) As frequency of oscillation of spring mass system,…
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