AP EAMCET · Maths · Probability
If \(A, B\) are two events with \(P(A \cup B)=0.65, P(A \cap B)=0.15\), then find the value of \(\mathrm{P}\left(\mathrm{A}^{\mathrm{C}}\right)+\mathrm{P}\left(\mathrm{B}^{\mathrm{C}}\right)\)
- A 0.8
- B 1
- C 1.2
- D 1.4
Answer & Solution
Correct Answer
(C) 1.2
Step-by-step Solution
Detailed explanation
Fact: \(\mathrm{P}(\mathrm{A} \cup \mathrm{B})=\mathrm{P}(\mathrm{A})+\mathrm{P}(\mathrm{B})-\mathrm{P}(\mathrm{A} \cap \mathrm{B})\) So \(P(A \cup B)+P(A \cap B)=P(A)+P(B)\) \(\Rightarrow \mathrm{P}(\mathrm{A})+\mathrm{P}(\mathrm{B})=0.65+0.15=0.8\), substitute the given values…
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