AP EAMCET · PHYSICS · Electrostatics
Two opposite charges each of magnitude \(500 \mu \mathrm{C}\) are \(10 \mathrm{~cm}\) apart. Find electric field intensity at a distance of \(25 \mathrm{~cm}\) from the midpoint on axial line of the dipole.
- A \(5.76 \times 10^7 \mathrm{NC}^{-1}\)
- B \(9.28 \times 10^7 \mathrm{NC}^{-1}\)
- C \(13.1 \times 10^{10} \mathrm{NC}^{-1}\)
- D \(20.5 \times 10^7 \mathrm{NC}^{-1}\)
Answer & Solution
Correct Answer
(A) \(5.76 \times 10^7 \mathrm{NC}^{-1}\)
Step-by-step Solution
Detailed explanation
Given, charge of dipole, \(q=500 \times 10^{-6} \mathrm{C}\) Separation between charges, \(2 a=10 \mathrm{~cm}\) \[ =10 \times 10^{-2} \mathrm{~m} \] Distance of location from mid point of axis, \[ r=25 \mathrm{~cm}=25 \times 10^{-2} \mathrm{~m} \] \(\because\) Electric field on…
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