AP EAMCET · PHYSICS · Wave Optics
If a slit of width ' \(x\) ' was illuminated by red light having wavelength \(6500 Å\), the first minima was obtained at \(\theta=30^{\circ}\). Then the value of ' \(x\) ' is
- A \(1.4 \times 10^{-4} \mu \mathrm{~m}\)
- B \(1.2 \times 10^{-5} \mathrm{~m}\)
- C \(1.3 \mu \mathrm{~m}\)
- D \(1.2 \mu \mathrm{~m}\)
Answer & Solution
Correct Answer
(C) \(1.3 \mu \mathrm{~m}\)
Step-by-step Solution
Detailed explanation
In diffraction, for first minima, \(\begin{aligned} & x \sin \theta=1 \times \lambda=6500 \times 10^{-10} \\ & \Rightarrow \quad x=\frac{6500 \times 10^{-10}}{\sin 30^{\circ}}=1.3 \mu \mathrm{~m} \end{aligned}\)
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