AP EAMCET · Maths · Quadratic Equation
If \(\alpha, \beta\) are the roots of the equation \(x^2-6 x-2=0\), \(\alpha\gt\beta\) and \(a_{\mathrm{n}}=\alpha^{\mathrm{n}}-\beta^{\mathrm{n}}, n\gt1\), then the value of \(\frac{a_{10}-2 a_8}{2 a_9}\) is equal to
- A 6
- B 4
- C 3
- D 2
Answer & Solution
Correct Answer
(C) 3
Step-by-step Solution
Detailed explanation
\(\begin{aligned} & \alpha^2-6 \alpha-2=0 \Rightarrow \alpha^{10}-2 \alpha^8=6 \alpha^9 ....(i)\\ & \beta^2-6 \beta-2=0 \Rightarrow \beta^{10}-2 \beta^8=6 \beta^9 .....(ii) \end{aligned}\)…
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