ExamBro
ExamBro
AP EAMCET · Maths · Quadratic Equation

If \(\alpha, \beta\) are the roots of the equation \(x^2-6 x-2=0\), \(\alpha\gt\beta\) and \(a_{\mathrm{n}}=\alpha^{\mathrm{n}}-\beta^{\mathrm{n}}, n\gt1\), then the value of \(\frac{a_{10}-2 a_8}{2 a_9}\) is equal to

  1. A 6
  2. B 4
  3. C 3
  4. D 2
Verified Solution

Answer & Solution

Correct Answer

(C) 3

Step-by-step Solution

Detailed explanation

\(\begin{aligned} & \alpha^2-6 \alpha-2=0 \Rightarrow \alpha^{10}-2 \alpha^8=6 \alpha^9 ....(i)\\ & \beta^2-6 \beta-2=0 \Rightarrow \beta^{10}-2 \beta^8=6 \beta^9 .....(ii) \end{aligned}\)…