AP EAMCET · PHYSICS · Magnetic Effects of Current
A short magnetic needle is placed in a magnetic field \(B \hat{i}\) in the direction \((\sqrt{3} \hat{i}+\hat{j})\).
The needle experiences a torque of \(0.06 \mathrm{~N}-\mathrm{m}\). If the same magnetic needle is placed in a magnetic field \(2 B \hat{j}\) in the direction \((\hat{i}+\sqrt{3} \hat{j})\), the torque experienced by it is
- A \(0.12 \mathrm{~N}-\mathrm{m}\)
- B \(0.84 \mathrm{~N}-\mathrm{m}\)
- C \(0.10 \mathrm{~N}-\mathrm{m}\)
- D \(0.03 \mathrm{~N}-\mathrm{m}\)
Answer & Solution
Correct Answer
(A) \(0.12 \mathrm{~N}-\mathrm{m}\)
Step-by-step Solution
Detailed explanation
( ) Torque on a magnet (dipole moment \(\mathbf{m}\) ) when it is placed in region of magnetic field (Intensity B) is \(\tau=\mathbf{M} \times \mathbf{B}\) Where, \(\mathbf{M}=\mathbf{M}\). \(\hat{\mathbf{u}}\) \(M=\) magnitude of dipole moment and \(\hat{\mathbf{u}}=\) unit…
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