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AP EAMCET · PHYSICS · Magnetic Effects of Current

A short magnetic needle is placed in a magnetic field \(B \hat{i}\) in the direction \((\sqrt{3} \hat{i}+\hat{j})\).
The needle experiences a torque of \(0.06 \mathrm{~N}-\mathrm{m}\). If the same magnetic needle is placed in a magnetic field \(2 B \hat{j}\) in the direction \((\hat{i}+\sqrt{3} \hat{j})\), the torque experienced by it is

  1. A \(0.12 \mathrm{~N}-\mathrm{m}\)
  2. B \(0.84 \mathrm{~N}-\mathrm{m}\)
  3. C \(0.10 \mathrm{~N}-\mathrm{m}\)
  4. D \(0.03 \mathrm{~N}-\mathrm{m}\)
Verified Solution

Answer & Solution

Correct Answer

(A) \(0.12 \mathrm{~N}-\mathrm{m}\)

Step-by-step Solution

Detailed explanation

( ) Torque on a magnet (dipole moment \(\mathbf{m}\) ) when it is placed in region of magnetic field (Intensity B) is \(\tau=\mathbf{M} \times \mathbf{B}\) Where, \(\mathbf{M}=\mathbf{M}\). \(\hat{\mathbf{u}}\) \(M=\) magnitude of dipole moment and \(\hat{\mathbf{u}}=\) unit…
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