AP EAMCET · PHYSICS · Work Power Energy
Two long parallel conducting wires carrying currents are separated by a distance ' \(x\) '. Work done per unit length in changing the distance between the wires is proportional to
- A \(\frac{1}{\log _{\mathrm{e}} x}\)
- B \(\frac{1}{x}\)
- C \(\log _e x\)
- D x
Answer & Solution
Correct Answer
(C) \(\log _e x\)
Step-by-step Solution
Detailed explanation
When conducting wire is displaced by \((x) d x\) distance, then work done per unit length is; \(d W=\mathrm{F} / \ell . d x\) or, \(\quad d W=\frac{\mu_0 I_1 I_2}{2 \pi x} d x\left[\because \frac{F}{\ell}=\frac{\mu_0 I_1 I_2}{2 \pi x}\right]\) or,…
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