AP EAMCET · Maths · Circle
The pole of the line \(x+y+2=0\) with respect to the circle \(x^2+y^2-4 x+6 y-12=0\) is
- A \((23,28)\)
- B \((-23,28)\)
- C \((23,-28)\)
- D \((-23,-28)\)
Answer & Solution
Correct Answer
(D) \((-23,-28)\)
Step-by-step Solution
Detailed explanation
\(2g = -4 \Rightarrow g = -2\) \(2f = 6 \Rightarrow f = 3\) \(c = -12\) Polar of \((x_1, y_1)\): \((x_1+g)x + (y_1+f)y + (gx_1+fy_1+c) = 0\) \((x_1-2)x + (y_1+3)y + (-2x_1+3y_1-12) = 0\) Compare with \(x+y+2=0\): \(\frac{x_1-2}{1} = \frac{y_1+3}{1} = \frac{-2x_1+3y_1-12}{2}\)…
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