AP EAMCET · PHYSICS · Atomic Physics
The ratio of longest wavelength lines in the Balmer and Paschen series of hydrogen spectrum is
- A \(\frac{5}{36}\)
- B \(\frac{7}{20}\)
- C \(\frac{7}{144}\)
- D \(\frac{5}{27}\)
Answer & Solution
Correct Answer
(B) \(\frac{7}{20}\)
Step-by-step Solution
Detailed explanation
\(\frac{1}{\lambda_{B L}}=R\left[\frac{1}{2^2}-\frac{1}{3^2}\right]=\frac{5}{36} R \Rightarrow \lambda_B=\frac{36}{5 R}\) ...(A) \(\frac{1}{\lambda_{P L}}=R\left[\frac{1}{3^2}-\frac{1}{4^2}\right]=\frac{7}{144} R \Rightarrow \lambda_P=\frac{144}{7 R}\) ...(B) On dividing Eq. (B)…
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